Tag Archives: rectangle

Distance between point and rectangular box without case logic

Assuming you have a point (x,y) and a rectangle parallel to x and y axis defined by its upper left and lower right corner. How can we calculate its distance without using case logic?

P = (x,y)
A = { (x1,y1), (x2,y2) }

The answer is:

dx = max(A.x1 - p.x, 0, p.x - A.x2)
dy = max(A.y1 - p.y, 0, p.y - A.y2)
distance = sqrt(dx*dx + dy*dy)

Its very tricky.

Here is a great analysis here by MultiRRomero:


Determine if two rectangles intersect without case logic

Assuming you have two rectangles A and B that exist parallel to the x and y axis and are defined by their upper left (x1,x2) and lower right corners (x2,y2). How can you calculate if A and B intersect without using case logic?

A = { (x1,y1), (x2,y2) }
B = { (x1,y1), (x2,y2) }




The answer is:

if (A.x1 < B.x2 && 
    A.x2 > B.x1 &&  
    A.y1 < B.y2 && 
    A.y2 > B.y1) {
  then A and B intersect

There is a great analysis here:


And an awesome interactive visualization by Matthew Crumley here: