Here is a small REGISTRY file which disables Windows Error Reporting.
This will disable the “Checking for solutions” popup.
Windows Registry Editor Version 5.00 [HKEY_CURRENT_USER\Software\Microsoft\Windows\Windows Error Reporting] "Disabled"=dword:00000001
Here is a list of configuration (registry) files for basic Windows 10 configuration:
For the official instructions (Tomcat 8), read this page
The following instructions are for development servers only:
For Windows:
"%JAVA_HOME%\bin\keytool" -genkey -alias tomcat -keyalg RSAFor Unix/Linux:
$JAVA_HOME/bin/keytool -genkey -alias tomcat -keyalg RSAYou will be asked for various information. Remember the password you typed at this step.
At the end of the procedure, keytool will create a file named “.keystore” to your home directory. By default it is hidden. This file should be moved to Apache-Tomcat home directory and can be renamed (eg to “keystore”).
Edit server.xml and comment out the following line:
<!--
Listener
className="org.apache.catalina.core.AprLifecycleListener"
SSLEngine="on"
/-->Edit server.xml and add (or uncomment and modify) the following lines:
<Connector
port="8443"
SSLEnabled="true"
protocol="org.apache.coyote.http11.Http11NioProtocol"
maxThreads="150"
scheme="https"
secure="true"
keystoreFile="keystore"
keyAlias="tomcat"
keystorePass="12345678"
clientAuth="false"
sslProtocol="TLS" />
You will have you replace “12345678” with your password.
You will also have to replace “keystore” with the full path to the keystore file generated at Step 1.
Do not forget to restart Apache-Tomcat
Before upgrading to Windows 10, check if there are drivers written for your hardware specifically for Windows 10. You should definitely check that drivers exists for your network card and your audio card.
This is because Windows 10 suffer from the same (and important) problem Windows 8 suffer: High DPC (deferred procedure call) latency. If the drivers do not work properly you may have high DPC latency, which may result to audio staggering, lag, clicks, drop outs even if your CPU does not reach 100%. This means that there is a high chance you won’t be able to playback movies flawlessly while using the network card! What a break dealer!!!
You can verify if your system suffers from high DPC latency by using LatencyMon. To learn what DPC latency is read this article.
If there is no Windows 10 driver for your network card, the easiest thing to do is not to upgrade to Windows 10 !!!
Now, what do we do if we have upgraded to Windows 10 and do suffer from undesired DPC latency? There are numerous solutions in the net. Most of which do not work.
Imho, You should complete the following steps by that order. If the problem is solved at any point, you don’t have to (and better not to) do the rest of the steps.
Step 1: Update your system.
Step 2: If possible, remove 3rd party antivirus and firewall software.
Step 3: Remove any software you don’t need (you should do that anyway)
Step 4: Update all drivers to latest version.
At this point, if the problem persists then most probably one of your drivers is faulty or not completely compatible with Windows 10. You can find which by using LatencyMon but you can bet it is the network/wireless driver.
The only thing you can do is rollback to an older version. So there are two more steps to do:
Step 5: Verify that the driver installed is for the correct hardware and not just for the correct hardware family. If your card is named 6200 then your driver should be for 6200. Anything else like 6201, 6205, 6300 is not acceptable.
Step 6: Find the proper driver for Windows 7 and install it
If the last step does not work, then you can try other drivers from the same family.
Lastly, if the problem still persists then there are two more steps but they are a long shot:
Step 7: Optimize BIOS :
Important settings to disable and may help are:
Step 8: Update the BIOS
Personally, I don’t think the last step helps. But many people claim it does, so you have nothing to lose.
Here are the official recommended settings for Wifi 802.11n from Intel:
| Property | Value |
| 802.11n channel width for band 2.4 | Auto (not in 20 MHz only) |
| 802.11n channel width for band 5.2 | Auto (not in 20 MHz only) |
| 802.11n mode | Enabled |
| Fat channel intolerant | Disabled |
| Roaming aggressiveness | Medium (or less) |
| Throughput enhancement | Disabled |
| Transmit power | Highest |
| Wireless mode | 802.11a/b/g |
| HT mode | VHT mode |
On the wireless router, check the following options:
| Property | Value |
| Auto channel scan | Enable |
| 802.11 mode | Use 802.11n only |
| Channel width | 40 MHz |
References:
https://www.intel.com/content/www/us/en/support/network-and-i-o/wireless-networking/000005544.html
Verify that your cat does not health problems that prevent her from consuming milk.
You will give her only a small amount of milk.
You need:
Step 1: Get a plastic cup:
Step 2: Cut the cup with scissors. Keep the base of the cup with 1cm approx height:
Step 3: Fill the cup with the milk, leave about 2mm empty
Step 4: Pour the medicine inside the cut cup.
Step 5: Stir
Step 6: Give it to the cat!
Done 🙂
In this post I describe the common problem how to generate random weighted variables. For example you have a die with 6 faces that is fixed, so the probability of an 1 is not the same with the probability of a 2 etc.
The table below shows an example:
| Face | Probability |
| 1 | 25 |
| 2 | 25 |
| 3 | 20 |
| 4 | 20 |
| 5 | 5 |
| 6 | 5 |
One easy solution is to reduce the problem to another one with a die with 100 faces that is not fixed.
You generate a random value from 0-99 that follows the uniform distribution. Do not use the modulo function to do that. See this post instead.
Once you have that value you perform the following steps:
You check the space within which that value relies.
Formulas shown below generate values that follow uniform distribution.
Using simple modulo methods is not considered as a good solution (although used a lot by students) as the module function does not generate all the variables with the same frequency.
int r = (int) (rand() / (RAND_MAX + 0.0));
int r = (int) (rand() / (RAND_MAX + 1.0));
int r = (int) (N * (rand() / (RAND_MAX + 0.0)));
int r = (int) (N * (rand() / (RAND_MAX + 1.0)));
int r = (int) (Μ + (rand() / (RAND_MAX + 0.0))*(N-M+1));
int r = (int) (Μ + (rand() / (RAND_MAX + 1.0))*(N-M+1));
The general formula is:
int r = (int) (A + (rand() / (RAND_MAX + C))*B);
Values of M, N, K are shown in the following table:
| Range | A | B | C |
| [ 0, 1 ] | 0 | 1 | 0.0 |
| [ 0, N ] | 0 | N | 0.0 |
| [ M, N ] | M | N – M + 1 | 0.0 |
| [ 0, 1 ) | 0 | 1 | 1.0 |
| [ 0, N ) | 0 | N | 1.0 |
| [ M, N ) | M | N – M + 1 | 1.0 |
Assuming you can already produce variables of uniform distribution, you can produce variables of normal distribution using various formulas. Two of the most important are:
Most methods are based on Box-Muller method.
The Marsaglia method is my favorite since it does not require using sin() or cos() functions and the steps are very easily to implement.
Here is a sequence of the steps:
Optionally you can add m to the quantities above to change the mean value of the distribution.
Java is tricky, you cannot add objects to already existent files with default classes.
Here is the solution:
import java.io.EOFException;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.ObjectInputStream;
import java.io.ObjectOutputStream;
import java.io.OutputStream;
public class Test{
private static String filename = "test";
public static void main(String[] args) {
writeToBinary (filename, "a", true);
writeToBinary (filename, "b", true);
writeToBinary (filename, "c", true);
readFromBinaryFile (filename);
}
public static void writeToBinary (String filename, Object obj, boolean append){
File file = new File (filename);
ObjectOutputStream out = null;
try{
if (!file.exists () || !append) out = new ObjectOutputStream (new FileOutputStream (filename));
else out = new AppendableObjectOutputStream (new FileOutputStream (filename, append));
out.writeObject(obj);
out.flush ();
}catch (Exception e){
e.printStackTrace ();
}finally{
try{
if (out != null) out.close ();
}catch (Exception e){
e.printStackTrace ();
}
}
}
public static void readFromBinaryFile (String filename){
File file = new File (filename);
if (file.exists ()){
ObjectInputStream ois = null;
try{
ois = new ObjectInputStream (new FileInputStream (filename));
while (true){
String s = (String)ois.readObject ();
System.out.println (s);
}
}catch (EOFException e){
}catch (Exception e){
e.printStackTrace ();
}finally{
try{
if (ois != null) ois.close();
}catch (IOException e){
e.printStackTrace ();
}
}
}
}
private static class AppendableObjectOutputStream extends ObjectOutputStream {
public AppendableObjectOutputStream(OutputStream out) throws IOException {
super(out);
}
@Override
protected void writeStreamHeader() throws IOException {}
}
}
References:
https://stackoverflow.com/questions/4646272/appending-objects-to-a-binary-file
